920 words  4 pages
Nicole Lynn Hicks
716 F Ave. #5
Coronado, CA. 92118 US
Evening Phone: 5094496253  Ext:
Day Phone: 5094496253  Ext:
Email: nlhicks662@msn.com
Availability: 
Job Type: Permanent, Recent Graduates, Internships
Work Schedule: FullTime, Shift Work 

Desired locations: 
United States  WA 

Work Experience:  
 
 FRCSW
Naval Air Station North Island
Coronado, CA 92118 United States
09/2015  Present
Salary: 56,595.00 USD Per Year
Hours per week: 40  Series: 0850 Pay Plan: GS Grade: 07 
Electrical Engineer (This is a federal job) 
Duties, Accomplishments and Related Skills: •Solving difficult electrical engineering
VIEW DOCUMENT
1067 words  5 pages
1
Running head: UNIT 4 ASSIGNMENT 1
Fundamentals of Finance
BUS 3062
Rodtrice Johnson
3/7/16
Unit 4 Assignment 1
Dennis Hart
1. Q: Proficientlevel: "How do Cornett, Adair, and Nofsinger define risk in the M: Finance textbook and how is it measured?" (Cornett, Adair, & Nofsinger, 2016).
Distinguishedlevel: Describe the risk relationship between stocks, bonds, and Tbills, using the standard deviation of returns as the measure of risk.
Answer Proficientlevel: Risk is defined as the volatility of an asset’s returns over time. Specifically, the standard deviation of returns is used to measure risk. This computation measures the deviation from the
VIEW DOCUMENT
1999 words  8 pages
Math 221
Quiz Review for Weeks 5 and 6
1. Find the area under the standard normal curve between z = 1.6 and z = 2.6.
2. A business wants to estimate the true mean annual income of its customers. It randomly samples 220 of its customers. The mean annual income was $61,400 with a standard deviation of $2,200. Find a 95% confidence interval for the true mean annual income of the business’ customers.
3. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An individual's IQ score is found to be 120. Find the zscore corresponding to this value.
4. Two high school students took equivalent language tests, one in German and one in French. The
VIEW DOCUMENT
668 words  3 pages
University of Phoenix Material
Time to Practice – Week Two
Complete Parts A, B, and C below.
Part A
1. Why is a z score a standard score? Why can standard scores be used to compare scores from different distributions?
2. For the following set of scores, fill in the cells. The mean is 74.13 and the standard deviation is 9.98.
Raw score Z score 
68.0 ? 
? –1.6 
82.0 ? 
? 1.8 
69.0 ? 
? –0.5 
85.0 ? 
? 1.7 
72.0
VIEW DOCUMENT
439 words  2 pages
(return  Inflation)
U.S. Gov. TBills 3.50% 2.90% 0.60%
Lg.cap CS 12.10% 2.90% 9.20%
L.T. Corp. Bonds 6.20% 2.90% 3.30%
L.T. Gov. Bonds 5.60% 2.90% 2.70%
SmallCap. CS 14.60% 2.90% 11.70%
2. The following are the monthly rates of return for Nike and JNJ
Using an excel spreadsheet, compute the following:
a. Average monthly rate of return for each stock
b. Standard deviation of returns for each stock
c. Covariance between the rates of return
d. The correlation coefficient between the rates of return
Month Nike JNJ
1 5% 8%
2 3% 1%
3 6% 2%
4 9% 11%
5 2% 4%
6 3% 6%
Mean 33% 3%
Standard Deviation 5.72% 6.13%
Covariance 0.00146667
Correlation
VIEW DOCUMENT
891 words  4 pages
gender. Quantitative variables include subjects that are numerical and give us a clear visual as to what the subject looks like. For instance, if we see a qualitative variable such as cat, we only know that the variable is a cat. A quantitative variable could tell us the weight of the cat, giving us a visual to compare the different sizes of the different cats, i.e. cat one weighs ten pounds, cat two weighs fifteen pounds. In this situation, the descriptive statistics are relatively useless when calculating gender (the qualitative data). The mean, mode, standard deviation and count are important in the quantitative data analysis because these types of statistical information hold value
VIEW DOCUMENT
1031 words  5 pages
Strayer University
MAT 300
Dr. Soosan Shahrokh
December 12, 2014
Bottling Company Case Study
In this project we were given the case of customer complaints that the bottles of the brand of soda produced in our company contained less than the advertised sixteen ounces of product. Our boss wants us to solve the problem at hand and has asked me to investigate. I have asked my employees to pull Thirty (30) bottles off the line at random from all the shifts at the bottling plant.
The next step in solving this problem is to calculate the mean (x bar), the median (mu), and the standard deviation (s) of the sample. All of those calculations were easily computed in excel. The mean was
VIEW DOCUMENT
282 words  2 pages
.Statistical Symbols and Definitions Matching Assignment
Match the letter of the definition on the right to the appropriate symbol on the left.
Symbols Definitions
1. S (Uppercase Sigma) B a. Null hypothesis
2. m (Mu) H b. Summation
3. s (Lowercase Sigma) E c. Factorial
4. p (Pi) I d. Nonparametric hypothesis test
5. e (Epsilon) G e. Population standard deviation
6. c2 (Chi Square) D f. Alternate hypothesis
7. ! C g. Maximum allowable error
8. H0 A h. Population mean
9. H1 F i. Probability
VIEW DOCUMENT
1010 words  5 pages
evaluating a security at the time when one year Treasury bills were paying 3.45%. Calculate the following investment’s expected return and standard deviation. Should BJ, a riskaverse investor, invest in this security?
State Probability Return
1 0.15 6%
2 0.30 10%
3 0.40 12%
4 0.15 16%
2. The common stocks of companies A and B have the expected returns and standard deviations given below; the expected correlation coefficient between the two stocks is –0.35.
Expected Return Standard Deviation
Common Stock A 0.10 0.15
Common Stock B 0.06
VIEW DOCUMENT
269 words  2 pages
tendency (mean, median or mode) do you think best describes the data set? Fully explain your answer.
Explain standard deviation
Explain what the standard deviation tells us about variation in our data.

**Remember to post substantial replies to at least two of your peers. You may find guidelines for acceptable response posts in the doc sharing portion of the course***
VIEW DOCUMENT
4199 words  17 pages
BKM CHAPTER 7
1. Which of the following factors reflect pure market risk for a given corporation?
a. Increased shortterm interest rates
b. Fire in the corporate warehouse
c. Increased insurance costs
d. Death of the CEO, e. Increased labor costs)
(a) and (e) – The other three do not affect all participants in the economy.
2. When adding real estate to an asset allocation program that currently includes only stocks, bonds, and cash alternatives (riskfreemoney market investments), which of the properties of real estate returns affect portfolio risk? Explain.
a. Standard Deviation
b. Expected Return
c. Correlation with the returns of
VIEW DOCUMENT
929 words  4 pages
monthly returns for Vanguard S&P 500 Index Fund, R.J. Reynolds and Hasbro. Among those return data, the Vanguard has a maximum return of 34.46% and a minimum return of 10.14. The Reynolds has a maximum return of 112.49 and a minimum return of 31.48. The Hasbro has a maximum return of 71.03 and a minimum return of 15.36. The result turns out that the Reynolds has the highest average return as 1.87% with a highest standalone risk measured by the standard deviation which is 8.116, while the Vanguard has the lowest average return as 0.57% with a lowest standard deviation 3.602 which means the lowest standalone risk. The sum of the five years’ returns for Vanguard is 34.46%, 112.49% for
VIEW DOCUMENT
2607 words  11 pages
= 9.1%
CV GH = 1.03.
[pic]S&P 50 = 16.4%.
CV S&P 50 = 1.10.
Standard deviation and coefficient of variation are measures of dispersion about the mean, and hence measure total risk. Total risk is the relevant measure of risk only for assets held in isolation.
Of the two total risk measures, coefficient of variation is the better one because it relates risk to the expected rate of return; that is, it standardizes the measure. (Note that a measure such as semivariance, which measures only downside risk, may be a better total risk measure than either standard deviation or coefficient of variation. However, if return distributions are approximately symmetric, then semivariance
VIEW DOCUMENT
297 words  2 pages
listening to music and solving math problems, and the brain area of interest has a percentage signal change of 58. From many previous studies with this same math problem’s procedure (but not listening to music), it is known that the signal change in this brain is normally distributed with a mean of 35 and a standard deviation of 10.
a. Using the .01 level, what should the researcher conclude? Solve this problem explicity using all five steps of hypothesis testing, and illustrate your answer with a sketch showing the comparison distribution, the cutoff (or cutoffs), and the score of the sample on this distribution.
Explain your answer to someone who has never had a course in statistics (but who is familiar with mean, standard deviation, and Z scores).
VIEW DOCUMENT
927 words  4 pages
programs
Chapter 4
3. An expert reviews a sample of 10 scientific articles (n = 10) and records the following numbers of error in each article: 0, 4, 2, 8, 2, 3, 1, 0, 5, and 7. Compute the SS, the variance, and the standard deviation for this sample using the definitional and computational formulas.
4. A psychologist interested in political behavior measured the square footage of the desks in the official office for four U.S. governors and of four chief executive officers (CEOs) of major U.S. corporations. The figures for the governors were 44, 36, 52, and 40 square feet. The figures for the CEOs were 32, 60, 48, 36 square feet.
a. Figure the means and standard deviations
VIEW DOCUMENT
2713 words  11 pages
Final Exam
Review Questions
Solutions Guide
You will probably want to PRINT THIS so you can carefully
check your answers. Be sure to ask your instructor if you have
questions about any of the solutions given below.
1. Explain the difference between a population and a sample. In
which of these is it important to distinguish between the two in order
to use the correct formula? mean; median; mode; range; quartiles;
variance; standard deviation.
Solution: A sample is a subset of a population. A population consists
of every member of a particular group of interest. The variance and
the standard deviation require that we know whether we have a
sample or a population.
2. The
VIEW DOCUMENT
1187 words  5 pages
value for significance level, α=0.05 for a lowertailed ztest is given as1.645.
Decision Rule: Reject H₀, if z – statistic, 1.645
Test Statistic in  minitab
OneSample Z: Income ($1000)
Test of mu = 50 vs < 50
The assumed standard deviation = 14.55
95% Upper
Variable N Mean StDev SE Mean Bound Z P
Income ($1000) 50 43.48 14.55 2.06 46.86 3.17 0.001
Interpretation of Results and Conclusion:
Since the Pvalue (0.0001) is smaller than the significance level (0.05), we reject the null hypothesis. The pvalue implies the probability of rejecting a true null hypothesis.
The significance level of 0.05, there is enough evidence to support the claim that the average annual
VIEW DOCUMENT
496 words  2 pages
standard deviation
The expected return of Barbara’s investment is 10.5% and the standard deviation is going to be 0.32 from the mean.
E(Rstock) = Ʃ4 i=1 (Pi x Ri)
= (0.1 x 0.25) + (0.4 x 0.15) + (0.3 x 0.10) + (0.2 x 0.05)
= 0.025 + 0.06 + 0.03 + 0.01
= 0.105 or 10.5%
= 0.105/4 = 0.02625
= √0.02625
σ = 0.1620185
Realized yield
The yield that Trevor will earn if the bond is sold today is $987.62 dollar.
Preferred stock valuation
The rate of return for the preferred stock is $91 dollar.
P˳ = D1 + P1 / 1 + R
= $1.65 + $100 / 1 + 1.116
= $91.08
References
Parrino, R., Kidwell, D. S, & Bates, T. W. (2012). Fundamentals of corporate finance (2nd Ed).
Hoboken, NJ: Wiley
Week 5 Assignment
VIEW DOCUMENT
901 words  4 pages
< 0.001) and low minimum cluster sizes (k > 8) is an ineffective control for multiple comparisons. We further argue that the vast majority of fMRI studies should be utilizing multiple comparisons correction as standard practice in the computation of their statistics.
To examine the spatial configuration of false positives we completed a variability analysis of the fMRI timeseries. On a voxelbyvoxel basis we calculated the standard deviation of signal values across all 140 volumes. We observed clustering of highly variable voxels into groups near areas of high voxel signal intensity. Figure 2a shows the mean EPI image for all 140 image volumes. Figure 2b shows the standard deviation
VIEW DOCUMENT
2554 words  11 pages
standard deviation of 2 minutes. In a sample, of 36 trials, the average time was 20 minutes. Test the claim against the alternative that the average time is not equal to 18 minutes, using a 0.01 level of significance.
Answer:
H0: The average time for a drug to take effect is 18 minutes. (μ= 18 mins.)
H1: The average time for a drug to take effect is not 18 minutes . (μ ≠ 18 mins.)
The two types of alternative hypotheses are:
1. Nondirectional alternative or twosided alternative  connotes inequality as indicated by ≠.
Examples:
H1: The mean fill per box is not 368 grams. ( μ ≠ 368)
H1: There is difference between males and females in their
performance
VIEW DOCUMENT
798 words  4 pages
error of the mean in the above output is a little over sixteen because that is
a. about half the sample size, and we use about 2 standard errors to calculate margins of error
b. the standard deviation divided by the square root of the sample size
c. the number of standard deviations from $675 d. the result of converting apartment size to square yards
e. None of the above
8. What does the interval (647.6 square feet, 702.9 square feet) tell us about onebedroom Orlando apartment size?
a. population mean has a 90% chance of lying within that interval
b. sample mean has a 90% chance of lying within that interval
c. 90% of onebedroom Orlando apartments have sizes within
VIEW DOCUMENT
928 words  4 pages
or increasing magnitude of variables.
To determine if there is no difference between the assessment of BFP personnel and RTC Judges who handled an arson case in terms of competency of BFP personnel in handling arson cases, the assessment was evaluated using standard deviation and TTest formula as shown below:
Standard Deviation :
σ=(X X)2n
σ = Standard Deviation
= sum of
X = Each value is the data set
X = mean of all values in the data set
N = number of value in the data set
T = X1 X2√s12n2+s22n2
x = mean
s = standard Deviation
n = sample
VIEW DOCUMENT
1152 words  5 pages
Quiz 2 Math 540
• Question 1
2 out of 2 points
If two events are not mutually exclusive, then P(A or B) = P(A) + P(B)
Answer
Selected Answer: False
Correct Answer: False
• Question 2
2 out of 2 points
Probability trees are used only to compute conditional probabilities.
Answer
Selected Answer: False
Correct Answer: False
• Question 3
2 out of 2 points
Seventy two percent of all observations fall within 1 standard deviation of the mean if the data is normally distributed.
Answer
Selected Answer: False
Correct Answer: False
• Question 4
0 out of 2 points
The equal likelihood criterion assigns a
VIEW DOCUMENT
1501 words  7 pages
taken to get said return?
Applying the Results
A positive alpha indicates the portfolio manager performed better than was expected based on the risk the manager took with the fund as measured by the fund's beta. A negative alpha means that the manager actually did worse than he or she should have given the required return of the portfolio. The regression results usually cover a period between 36 and 60 months.
b) Standard deviation
Standard deviation is a measure of how "spread out" a set of data is. If it is large, you have a large range of numbers. If it is small, most of your data points are close to the average.
To find it, you need to subtract the "mean" (average) of the data from
VIEW DOCUMENT
2610 words  11 pages
expansion in a flexible business plan.
Various executive compensation plans have been employed to motivate managers to make decisions that maximize shareholder wealth. These include:
Correct Answer:
requiring officers to own stock in the company
• Question 6
The moral hazard in team production arises from
Correct Answer:
a conflict between tactically best interest and one’s duty
• Question 7
The level of an economic activity should be increased to the point where the ____ is zero.
Correct Answer:
net marginal benefit
• Question 12
The approximate probability of a value occurring that is greater than one standard deviation from the mean is approximately
VIEW DOCUMENT
1205 words  5 pages
the regular season. Consider his next 8 free throws. 3) What is the probability that he will make exactly 6 free throws? A) 0.1468 B) 0.3355 C) 0.2936 4) What the probability that he will make at least 6 free throws? A) 0.2936 B) 0.3355 C) 0.7969
D) 0.1678 D) 0.1468
THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: A cereal manufacturer produces a cereal that claims to contain 16 ounces in each box. A sample of boxes results in the following table. 14 15 16 17 Weight in Ounces Probability 0.10 0.30 0.40 0.20 5) What is the mean weight of the sample of cereal boxes? A) 16.0 B) 15.7
C) 15.5
D) 16.5 D) 1.25
6) What is the standard deviation of the weight of cereal in the
VIEW DOCUMENT
549 words  3 pages
experiment consists of tossing an unbiased coin three times. Drawing a probability tree for this experiment will show that the number of simple events in this experiment is
8
Use the following information to answer questions 6 and 7: The weights of newborn children in the United States vary according to a normal distribution with mean 7.5 pounds and standard deviation 1.25 pounds. The government classifies a newborn as having low birth weight if the weight is less than 5.5 pounds.
What proportion of babies weigh less than 5.5 pounds at birth?
0.0548
If the government wanted to change the value 5.5 pounds to a weight where only 2% of newborns weigh less than the new value, what
VIEW DOCUMENT
7978 words  32 pages
314477.18
Standard deviation 10356.25 1176.32 105517.62 11985.30
Average returns 0.05369850 0.11683823 0.05345001 0.01097722
DC 60 DB 60 DC 65 DB 65
6789419.11 5220118.40 10161618.05 7633917.85
3668195.63 416654.74 6079058.02 690494.34
0.05266843 0.04789184 0.05245102 0.04839546
Simulated required outputs without 7% contribution
DC 28 NC DB 28 NC DC 35 NC DB 35 NC
Average lump sum benefit 50216.33 36508.82 265650.87 199360.22
Standard deviation 6665.83 0.00 67916.69 0.00
VIEW DOCUMENT
1742 words  7 pages
natural cycle.
The null hypothesis: µ = 24
The alternative hypothesis: µ ≠ 24
2. Define the features of the compared distribution
Sample mean: 25 M = (∑X)/N = 200/8 = 25
Sample Standard deviation: 1.195229 SD √ SD^2 =
Find the estimated population variance. You first need to figure the sample mean, which is (25+27+25+ 23+24+25+26+ 25)/8 = 200/8 = 25. The estimated variance population is S^2 = SS/(N1) = [( 2525)^2 + ( 2725)^2 + (2525)^2 + (2325)^2 + (2425)^2 + (2525)^2 + (2625)^2+( 2525)^2] / (81) = ( 0^2 + 2^2 + 0^2 + 2^2 + 1^2 + 0^2 + 1^2 + 0^2) /7 = ( 0 + 4+ 0 + 4 +1 + 0+1+0)/7 = 10/7 = 1.43
Finding the variance of the distribution of mean:
S^2/M = S^2
VIEW DOCUMENT
5048 words  21 pages
statistics
As mentioned in the text, descriptive statistics is a science of describing the important aspects of a set of measurements (Bowerman). The measures of central tendency measures mean, median and mode. The measures of variation measures range, standard deviation and variance. The mean is sum of numbers divided by the total numbers. As explained in encyclopedia2 of the free dictionary website, the arithmetic mean is found by adding the numbers and dividing the sum by the number of numbers in the list (Farflex, Inc). This is what is most often meant by an average. The median is the middle value in a list ordered from smallest to largest (Farflex, Inc). The mode is the most frequently
VIEW DOCUMENT
385 words  2 pages
Question 1
If we ignore tax considerations and assume that Sally Jameson is free to sell her options at any time after she joins Telstar she has several chooses.
She can either choose to take the cash bonus, either take the options and sell it, or she can take the option and keep it until it is worth use.
Let’s compare the situations :
1 She takes the cash bonus and decide to invest it in a 5year bond which rate is 6,02%.
So at the end she will win 5310$ (=5000*1,0602).
2 She takes the options in order to sell it.
Let’s assume that it is easy to find someone who want to buy the option at the value of the call option.
Seeing the exhibit 3, the standard deviation of
VIEW DOCUMENT
453 words  2 pages
not known when next orders will be placed.
Analysis
Option A – 25 regular car shipments with additional safety stock done at a fixed cycle of 14 days or 2 weeks will provide a net savings of $183,525. Deciding on this option allows Large Bakers to cover unexpected demand with a standard deviation estimated at 300 tons. With a fixed order cycle, the company will be guaranteed on time loading and delivery of shipment. However, with the additional safety stock, we are likely to incur more carrying costs.
Option B – Orders done in variable intervals will provide Large Bakers an annual cost savings of 224,204.50. This is due to the orders only being made when our inventory reaches the
VIEW DOCUMENT
4098 words  17 pages
simulate for 500.
Exercise 98
Parts are arriving with an interarrival time that is exponentially distributed and has a mean of 50 seconds. There are three types in the following proportions: A, 30%; B, 20%; and C, 50%. A separate machine is to be used for each type and the simulation is to produce individual statistics for the three machines. The time to machine a part is normally distributed with a mean of 90 seconds and a standard deviation of 15 seconds for all types. Simulate the system, using a function as an SNA to supply the facility number.
Exercise 101
Records are being read from a poor quality tape. There is a chance of 1 in 50 that the record will be bad on the
VIEW DOCUMENT
753 words  4 pages
Euy Hyun Chong
N9718605
Euy Hyun Chong
N9718605
Numerical descriptive measures
Take Home Assignment  Topic 2
Numerical descriptive measures
Take Home Assignment  Topic 2
Question 1:
Data Set         
11  12  14  15  16  18  24  25  28  32 
Min  Quartile 1   Median   Quartile 3  Max 
Table [ 1 ]. Ages of 10 randomly selected students in a Judo school in Brisbane.
(a) Mean (x) : 19.5
Standard Deviation (S) : 7.24568
(b) Median: 16+182=17
When comparing the mean and the median it tells the distribution is skewed to the right, which is positively skewed. The skewness of the dataset is positive due to bigger mean value
VIEW DOCUMENT
2837 words  12 pages
 0.1341 
0.602  0.352  0.1463 
0.482  0.315  0.1820 
0.419  0.296  0.2057 
0.334  0.264  0.2579 
The errors that will be used are the values that were the highest for each of the balls. Therefore the propagation of error for each ball is δg13=0.2579 and δg16=0.2541.
The precision of the timer also needs to be considered. The precision of measurement can be judged by the standard deviation, Δt. SD expresses the spread of measured values about their average. To calculate the standard deviation of time, a small experiment must be performed. The small experiment consists of dropping the 13mm ball ten times using a standard height. The standard height used was 0.997m. The
VIEW DOCUMENT
1026 words  5 pages
Problems Formulation and Identification
Problem identification and formulation is the most critical element of the decisionmaking process. Problems defined as perceived gaps between an existing state and the desired state, a deviation from the norm, status quo or set standard; difficulties arise when the solution to mend the deviation is not clear.
Problem Formulation
Widely known, is a well formulated problem is a problem nearly solved. Breaking up a complex and unclear situation into a set of individual, welldefined problems is vital to finding solutions, (Problem Formulation, 2005).
An activity aimed at identifying a problem by specifying the undesirable and
VIEW DOCUMENT
1597 words  7 pages

Number of Cigarettes smoked Daily Age Weak
Statistics and Correlation Results
FIGURE 2:
Measure of Central Tendency and Variability with Regard to Age 
Mean  34 
Standard Error  0.76 
Median  30 
Mode  29 
Standard Deviation  13 
Range  72 
Minimum  13 
Maximum  80 
Count  327 
 
Figure 2: Summarizes the measure of central tendency and variability with regard to age. Note that the mean age of respondents was 34. The mean is the score located at the mathematical center of a distribution. Thus this is the average age of all respondents in the survey. The standard deviation
VIEW DOCUMENT
1741 words  7 pages
Descriptive statistics such as frequency count, mean score and standard deviation (SD) are used to explain the data. Environmental factors are described based on the level of satisfaction and agreement as reported from feedbacks. The interpretation of the level of satisfaction and agreement is based on the interpretation of mean scores using the Nunnally formula (1978) (Table 1). CGPA is interpreted in accordance to the interpretation by the National University of Malaysia (UKM) (Table 2).
Table 1 Mean Interpretation for Environment and Output Factors
MEAN INTERPRETATION
VIEW DOCUMENT
2361 words  10 pages
will lead to enormous carrying cost expense and will defeat the purpose of not wanting to lose demand. Already we carry two weeks’ worth of inventory for all types of models and this may not be efficient. Here we analyze to see if any improvements can be made on this already adopted strategy.
Safety Stock Analysis:
Refer to Figure 1 in Appendix section.
According to the case, FS keeps two weeks’ worth of safety stock for all mattress models. Hence, we assume the leadtime of order is 2 weeks. Let
AVG = the average demand per time unit
STD = the standard deviation of demand per time unit
L = the leadtime of order
D = the average demand during the leadtime
L= the standard of deviation
VIEW DOCUMENT
1362 words  6 pages
same in consultation with ASB. The Accounting Standard on the relevant subject will then be issued under the authority of the Council.
Compliance with the Accounting Standards:
While discharging their attest functions, it will be duty of the members of the Institute to ensure that the Accounting Standards are implemented in the presentation of financial statements covered by their audit reports.
In the event of any deviation from the Standards, it will also be their duty to make adequate disclosures in their reports so that the users of such statements may be aware of such deviations.
In the initial years, the Standards will be recommendatory in character and the Institute will give wide
VIEW DOCUMENT
2475 words  10 pages
are further divided into: zscores, which represent an individual's distance from the mean in standard deviation units. A raw score equal to the mean, has a zscore of '0'. Positive zscores indicate and above average performance. Linearly transformed standard scores, are a transformation of the zscores to eliminate the limited range of a zscore distribution. Normalised standard scores are standard scores that have been transformed to fit a normal distribution. (An Introduction to Psychological Assessment. Foxcroft and Roodt.p60). This is done if it is assumed that a particular attribute is normally distributed. McCall's T scores eliminated negative values, and allows for a standard scale
VIEW DOCUMENT
570 words  3 pages
Reporting Statistics in APA Style
Dr. Jeffrey Kahn, Illinois State University
The following examples illustrate how to report statistics in the text of a research report. You will note that significance levels in journal articlesespecially in tablesare often reported as either "p > .05," "p < .05," "p < .01," or "p < .001." APA style dictates reporting the exact p value within the text of a manuscript (unless the p value is less than .001).
Please pay attention to issues of italics and spacing. APA style is very precise about these. Also, with the exception of some p values, most statistics should be rounded to two decimal places.
Mean and Standard Deviation are most clearly
VIEW DOCUMENT
1934 words  8 pages
Chapter 6. Risk, Return, and CAPM
Dollar return: Amount to be receivedAmount invested
Rate of return: Amount receivedAmount investedAmount invested
Standalone risk is the risk an investor has in just holding the one asset
Expected rate of return: r=i=1npiri Where P is probability of i outcome and r is the rate of return
The more leptokurtic the distribution, the more likely the actual outcome will be closer to the expected return.
Measuring Standalone Risk: Standard Deviation
1. Expected Rate of return
2. Deviationi= rir
3. Variance=σ2=i=1n( rir)2Pi
4. Standard Deviation=σ=Variance
5. Or use Excel of Financial calculator
Using Historical Data to Measure
VIEW DOCUMENT
568 words  3 pages
be proposed to enhance the effectiveness of the PTA in extending help to schools?
This study used the descriptivecorrelational type of research, utilizing a set of questionnaire to gather data on the complementary role of the ParentTeacher Association and documentary analysis of the areas of school performance. The data gathered were scored, tallied and tabulated, and were statistically treated employing frequency mean, Standard Deviation, correlation procedures and coefficient of determination.
Based on the foregoing significant results of this study, the following conclusions are drawn:
1. The total enrolment of Bagabag I during the SY 20122013 in Bagabag I District is good for
VIEW DOCUMENT
534 words  3 pages
QRB 501 Entire Course (UOP Course)
For more course tutorials visit
www.tutorialrank.com
QRB 501 Week 1 Quiz (New)
QRB 501 Week 2 Learning Team Case Studies (52 and 62) (New)
QRB 501 Week 2 Quiz (New)
QRB 501 Week 2 Problem Set (New)
QRB 501 Week 3 Learning Team Case Studies (83 and 91) (New)
QRB 501 Week 3 Quiz (New)
QRB 501 Week 3 Problem Set (New)
QRB 501 Week 4 Team Assignment Standard Deviation Abstract (New)
QRB 501 Week 4 Quiz (New)

QRB 501 Week 1 DQ 1 (UOP Course)
For more course tutorials visit
www.tutorialrank.com
In management, how important is it to learn to use mathematics to solve
VIEW DOCUMENT
3360 words  14 pages
%   Total Variance = 71.26 
Standard Deviation for A = 73.56 = 8.58%
Standard Deviation for B = 71.26 = 8.44%
Probability  RAERA  RBERB  P (RAERA) (RBERB) 
0.3  2716.8 = 10.2  3522.5 = 12.5  38.25 
0.4  1816.8 = 1.2  1522.5 = 7.5  3.6 
0.3  5.016.8= 11.8  2022.5 = 2.5  8.85 
   Total (COV AB)= 43.5 
Correlation Coefficient = rAB = COVABσA x σB = 43.58.58 x 8.44 = 0.6
Degree of risk of the portfolio in (a):
σp=WA²σA²+WB²σB²+2WAWB(rAB)(σA)(σB)
= 0.44²8.58²+0.56²8.44²+20.440.560.68.58(8.44)
= 58
= 7.62
(c).
If Gawain’s existing activities have a standard deviation of 10%, the risk will be decreases when
VIEW DOCUMENT
1415 words  6 pages
All of the models to be discussed, i.e. Markowitz, Single Index, CAPM, and APT, have one single goal that is accomplished by using them. This goal is to make a portfolio, or individual securities, as efficient and well performing as possible by finding the optimal weights, highest return, and lowest risk.
The Harry Markowitz model of 1952, or the meanvariance model, was one of the earliest models created to compare and contrast securities outcomes. This model uses the weights, standard deviation, and covariance for each security, creating a weighted covariance matrix, therefore forecasting a very accurate estimate of what return and risk the securities or portfolio would give.
The
VIEW DOCUMENT
1108 words  5 pages
newsstands. It has also determined that the ages of its subscribers are normally distributed with a mean of 44.5 and a standard deviation of 7.42 years, whereas the ages of its newsstand customers are normally distributed with a mean of 36.1 and a standard deviation of 8.20 years.
(a) Find the middle 80% range (i.e. range that is symmetrical about the mean) for the age of its subscribers.
(b) What proportion of Mogul’s newsstand customers have ages in the range computed above?
(c) What proportion of all of Mogul’s customers have ages in the range given in (a).
Question 5
Suppose that a student is taking a multiplechoice exam in which
VIEW DOCUMENT