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Determining The Activation Energy Of The Reaction Between Bromide Ion And Bromate Ion In Acid Solution

572 words - 3 pages

Determining the Activation Energy of the Reaction Between Bromide Ion and Bromate Ion in Acid Solution

Objectives:

By reacting Potassium Bromide and Potassium Bromate in the acid
solution in varies temperature, we can then determine the Activation
Energy of the reaction in different temperature through the equation:[IMAGE].

Results:

Experiment Temperature

Time t/s

ln 1/t

Temperature K

1/K

80

≒0

N/A

353

2.83286119*10-3

50

21

-3.044522438

324

3.086419753*10-3

45

27

-3.295836866

316

3.164556962*10-3

40

42

-3.737669618

315

3.174603175*10-3

35

70

-4.248495242

311

3.215434084*10-3

30

113

-4.727387819

304

3.289473684*10-3

Questions:

1. ...view middle of the document...

So it is not advisable to perform the
experiment at high temperatures as the time of reaction is too short,
it is not easy for us to record.

4. Why is it not necessary to know how far the reaction has proceeded
at the point where the methyl red is decolourized?

In the experiment, the number of mole and the molarity of each
chemicals used are the same. And the appearance of the pink colour
only determines that there are some content of the reaction has
processed. As the result, it is only necessary for us to compare the
time required for the reaction mixture to reach the point the
decolourization occurs at different temperature.

5. The Arrhenius equation can be represented as: [IMAGE]

(a) Can [IMAGE] substitute k in this equation? Why?

[IMAGE] can substitute k in this equation. As in the above experiment,
the initial rate can be represented by [IMAGE] due to the constant
concentration of the reactants. Also the rate constant k is
proportional to the rate of the reaction when the temperature changes.
Therefore, [IMAGE] can substitute k.

(b) Derive an equation relating ln k and 1/T.

[IMAGE]

ln k = ln A – Ea/RT

ln k = ln A – (Ea/R)(1/T)

(c) Determine Ea by plotting a suitable graph. (Given R=8.3JK-1 mol-1
)

[IMAGE]

Slope=ï¼»-4.727387819-(-3.044522438)ï¼½/(3.289473684*10-3-3.086419753*10-3)

=-8287.78

∵ lnk = lnA – Ea/RT

The slope=-Ea/R

∴-8287.78=-Ea/R

Ea=8287.78*8.314

=68904.6 J mol-1

=68.9046 kJ mol-1

6. Explain why the reaction rate can be affected by temperature.

As the temperature increase, the numbers of vibration increase, the
speed of the particles increase, then the frequency of collision
increases. As the result, the frequency of effective collision also
increases. Therefore the reaction rate will increase vice versa.

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